Difference between revisions of "Cubic Step Function Softening"
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<math> | <math>\Omega(\delta,s) = {\delta \over 2} | ||
\left(1+\left({\delta\over \delta_{max}}\right)^2\left(\frac{4k_2-1}{3}-k_2{\delta\over \delta_{max}}\right)\right)</math> | \left(1+\left({\delta\over \delta_{max}}\right)^2\left(\frac{4k_2-1}{3}-k_2{\delta\over \delta_{max}}\right)\right)</math> | ||
Revision as of 09:54, 9 July 2021
The Softening Law
This softening law was originally a step function (hence the name), but was latter generalized to allow it to be a cubic function that can optionally rise to a peak before decaying to zero at [math]\displaystyle{ \delta_{max} }[/math]. The function is
[math]\displaystyle{ f(\delta,s) = \left(1+2k_2{\delta\over \delta_{max} }\right)\left(1-{\delta\over \delta_{max} }\right)^2 \quad{\rm where}\quad k_2 = 1+\frac{k}{2} }[/math]
This cubic function has [math]\displaystyle{ f(0)=1 }[/math], [math]\displaystyle{ f'(0)= k/\delta_{max} }[/math], and [math]\displaystyle{ f(\delta_{max})=f'(\delta_{max})=0 }[/math]. The value for [math]\displaystyle{ \delta_{max} }[/math] is found from
[math]\displaystyle{ sG_c = \int_0^{\delta_{max}} f(\delta,s) = {\delta_{max}\over 2}\left(1+\frac{k}{6}\right) \quad{\rm or}\quad \delta_{max} = \frac{2sG_c}{1+\frac{k}{6}} }[/math]
Here s is the softening scaling term and Gc is toughness of the law (and the law's only property). The critical cracking strain, [math]\displaystyle{ \delta_{max} }[/math], which depends on mesh size and crack orientation, is calculated from s and Gc and is not a law property to be provided.
If [math]\displaystyle{ k=0 }[/math], this law is a cubic step function with [math]\displaystyle{ f'(0)=0 }[/math], but if [math]\displaystyle{ k\gt 0 }[/math], this function rises to a peak and then decays to failure at [math]\displaystyle{ \delta_{max} }[/math] (see plots on the right). This behavior is valid for softening laws provided the modulus still monotonically softens. When using [math]\displaystyle{ k\gt 0 }[/math], you enter the initial stress into the initiation law. If you want to set the peak stress, the initiation stress should be calculated from the desired peak using:
[math]\displaystyle{ \sigma_{0} = \frac{\left(1+\frac{k}{2}\right)^2}{\left(1+\frac{k}{3}\right)^3}\sigma_{peak} }[/math]
The area (or energy dissipation term) is
[math]\displaystyle{ \Omega(\delta,s) = {\delta \over 2} \left(1+\left({\delta\over \delta_{max}}\right)^2\left(\frac{4k_2-1}{3}-k_2{\delta\over \delta_{max}}\right)\right) }[/math]
The stability factor is:
[math]\displaystyle{ \eta = \frac{12k_2}{(1+2k_2)^2k_6} }[/math]
If [math]\displaystyle{ k=0 }[/math], the stability factor simplifies to [math]\displaystyle{ \eta = 4/3 }[/math], or slightly less stable than a linear softening law. Potentially, the zero derivative at [math]\displaystyle{ \delta_{max} }[/math] could improve modeling of failure. The stability factor decreases as [math]\displaystyle{ k }[/math] increases.
Softening Law Properties
Only one property is needed to define a cubic step function softening law:
Property | Description | Units | Default |
---|---|---|---|
Gc | The toughness associated with the this softening law | energy release units | none |
k | Initial slope of the law (must be nonnegative) (OSParticulas only) | none | 0 |