Difference between revisions of "Orthotropic Failure Surface"

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== Failure Surface ==
== Failure Surface ==


This failure surface has nine failure properties. First, are three tensile strengths <math>\sigma_{ii}^{(c)}</math> where i is x, y, or z that give tensile strength in the three material direciton
This failure surface has nine failure properties. First, are three tensile strengths <math>\sigma_{ii}^{(c)}</math> where i is x, y, or z that give tensile strength in the three material directions. Second, are six shear strengths <math>\tau_{ij,i}^{(c)}</math> that give the shear in the three material symmetry planes (with ij = xy, xa, or yz). The second index gives the direction of the shear crack in that plane and the crack has normal in in the j direction. Each shear plane has two shear strengths. Failure initiates by shear when:


Second, are six shear strengths <math>\tau_{ij,i}^{(c)}</math> that give the shear in the three material symmetry planes (with ij = xy, xa, or yz). When shear in one of these reaches this stress, the material initiates damage. The second index give the direction of the shear crack in that plane. For example,
&nbsp;&nbsp;&nbsp;&nbsp;
<math>\tau_{ij}  > \min\bigl(\tau_{ij,i}^{(c)},\tau_{ij,j}^{(c)}\bigr)</math>


<math>       \tau_{ij}  > \min\bigl(\tau_{ij}^{(i,c)},\tau_{ij}^{(j,c)}\bigr) \ &{\rm with}\
The crack that forms is in the i direction with normal in the <math>{\hat j}</math> direction if <math>\tau_{ij,i}^{(c)} < \tau_{ij,j}^{(c)}</math>, otherwise the crack normal is in the <math>{\hat i}</math> direction.
                              \hat{\vec n} = \left\{ \begin{array}{ll}
                                          \vec{\hat j} & {\rm if}\ \tau_{ij}^{(i,c)}<\tau_{ij}^{(j,c)} \\
                                          \vec{\hat i} & {\rm if}\ \tau_{ij}^{(i,c)}>\tau_{ij}^{(j,c)}
                                      \end{array}\right.
</math>
 
The first two shear strength are for failure at maximum shear stress in planes parallel to the axial direction. When failure occurs in such a plane, the resulting crack will either be parallel to the axial direction with normal in transverse direction (if <math>\tau_A < \tau_T</math>) or parallel to the transverse direction with normal in the axial direction (if <math>\tau_T< \tau_A</math>) . The last shear strength is for failure in the isotropic plane, which occurs in the maximum shear stress direction in that plane.


== Damage Law Properties ==
== Damage Law Properties ==
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! Property !! Description !! Units !! Default
! Property !! Description !! Units !! Default
|-
|-
| sigmacA || Critical stress for failure in the axial direction (output as <tt>sigcA</tt>) || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
| sigmaXXc || Critical stress for failure by tension in the material x direction || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
| sigmaYYc || Critical stress for failure by tension in the material y direction || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
| sigmaZZc || Critical stress for failure by tension in the material z direction || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
| tauXY-Xc || Critical stress for failure by shear in the material x-y plane. The crack that forms is in the x direction with normal in the y direction. || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
| tauXY-Yc || Critical stress for failure by shear in the material x-y plane. The crack that forms is in the y direction with normal in the x direction. || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
|-
| sigmac ||Critical transverse tensile strength for tensile failure in the isotropic plane (output as <tt>sigcT</tt>) || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
| tauXZ-Xc || Critical stress for failure by shear in the material x-z plane. The crack that forms is in the x direction with normal in the z direction. || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
|-
| taucA || Critical shear stress for failure due to axial shear stress with failure parallel to the axial direction || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
| tauXZ-Zc || Critical stress for failure by shear in the material x-z plane. The crack that forms is in the z direction with normal in the x direction. || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
|-
| taucT || Critical shear stress for failure due to axial shear stress with failure through the axial direction || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
| tauYZ-Yc || Critical stress for failure by shear in the material y-z plane. The crack that forms is in the y direction with normal in the z direction. || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|-
|-
| tauc ||Critical transverse shear stress for shear failure n the isotropic plane (output as <tt>taucRS</tt>) || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
| tauYZ-Zc || Critical stress for failure by shear in the material y-z plane. The crack that forms is in the z direction with normal in the y direction. || [[ConsistentUnits Command#Legacy and Consistent Units|pressure units]] || infinite
|}
|}


Notice this law has two axial shear strengths (<tt>taucA</tt> and <tt>taucT</tt>). If failure occurs by shear in a plane parallel to the axial direction, the failure and crack orientation will be determined by the minimum of taucA and taucT. Even though the maximum value is never used to initiate failure, it is still needed for damage evolution. For example, in wood, <tt>taucA</tt> is called "shear parallel strength", <tt>tauT</tt> is called "shear perpendicular strength", and <tt>tauc</tt> is called "rolling shear strength". For wood, <tt>tauT</tt> is much larger than <tt>taucA</tt>, which means shear failure is by shear cracks parallel to the wood fibers in the axial direction. But, if the wood initiates failure by tension parallel tot he fibers and then is loaded in shear, the shear damage evolution will be determined by softening law based on <tt>tauT</tt>.
Even though the maximum shear value for each ij plane is never used to initiate failure, they are still needed for damage evolution. For example, if the material initiates failure by tension in the x direction, the shear damage evolution will be determined by softening laws based on shear strengths with the same normal (''i.e.'', tauXY-Yc and tauXZ-Zc) even if they are larger that the other shear strengths for those planes.

Latest revision as of 23:09, 20 February 2020

Introduction

This damage initiation law predicts failure in orthotropic materials. Because it deals with a specific material type, this law is only appropriate for OrthoSoftening materials.

Failure Surface

This failure surface has nine failure properties. First, are three tensile strengths [math]\displaystyle{ \sigma_{ii}^{(c)} }[/math] where i is x, y, or z that give tensile strength in the three material directions. Second, are six shear strengths [math]\displaystyle{ \tau_{ij,i}^{(c)} }[/math] that give the shear in the three material symmetry planes (with ij = xy, xa, or yz). The second index gives the direction of the shear crack in that plane and the crack has normal in in the j direction. Each shear plane has two shear strengths. Failure initiates by shear when:

     [math]\displaystyle{ \tau_{ij} \gt \min\bigl(\tau_{ij,i}^{(c)},\tau_{ij,j}^{(c)}\bigr) }[/math]

The crack that forms is in the i direction with normal in the [math]\displaystyle{ {\hat j} }[/math] direction if [math]\displaystyle{ \tau_{ij,i}^{(c)} \lt \tau_{ij,j}^{(c)} }[/math], otherwise the crack normal is in the [math]\displaystyle{ {\hat i} }[/math] direction.

Damage Law Properties

The following table lists the input properties for this initiation law

Property Description Units Default
sigmaXXc Critical stress for failure by tension in the material x direction pressure units infinite
sigmaYYc Critical stress for failure by tension in the material y direction pressure units infinite
sigmaZZc Critical stress for failure by tension in the material z direction pressure units infinite
tauXY-Xc Critical stress for failure by shear in the material x-y plane. The crack that forms is in the x direction with normal in the y direction. pressure units infinite
tauXY-Yc Critical stress for failure by shear in the material x-y plane. The crack that forms is in the y direction with normal in the x direction. pressure units infinite
tauXZ-Xc Critical stress for failure by shear in the material x-z plane. The crack that forms is in the x direction with normal in the z direction. pressure units infinite
tauXZ-Zc Critical stress for failure by shear in the material x-z plane. The crack that forms is in the z direction with normal in the x direction. pressure units infinite
tauYZ-Yc Critical stress for failure by shear in the material y-z plane. The crack that forms is in the y direction with normal in the z direction. pressure units infinite
tauYZ-Zc Critical stress for failure by shear in the material y-z plane. The crack that forms is in the z direction with normal in the y direction. pressure units infinite

Even though the maximum shear value for each ij plane is never used to initiate failure, they are still needed for damage evolution. For example, if the material initiates failure by tension in the x direction, the shear damage evolution will be determined by softening laws based on shear strengths with the same normal (i.e., tauXY-Yc and tauXZ-Zc) even if they are larger that the other shear strengths for those planes.